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x^2-24x=-72
We move all terms to the left:
x^2-24x-(-72)=0
We add all the numbers together, and all the variables
x^2-24x+72=0
a = 1; b = -24; c = +72;
Δ = b2-4ac
Δ = -242-4·1·72
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-12\sqrt{2}}{2*1}=\frac{24-12\sqrt{2}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+12\sqrt{2}}{2*1}=\frac{24+12\sqrt{2}}{2} $
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